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#1
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500 hundreds of a inch
500 hundreds of a inch, dose A LOT of really bad stuff (to put it in simple form)
our 80-20 got messed up some how??? in two place off by 500 hundreds of a inch WHO KNOW HOW!!! just take time to fix it NO BIGGIE ![]() |
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#2
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Re: 500 hundreds of a inch
500ths of an inch is much larger than you think, a millimeter is 1/254 (if i remember correctly, maybe 1/245). and 1 millimeter is visible to us, it can be a huge gap with machinery or instruments. a nut that is 1/500ths larger than its bolt wont fit if that gives a better sense...
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#3
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Re: 500 hundreds of a inch
Quote:
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#4
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Re: 500 hundreds of a inch
must have been a typo, but i see your point. he probably meant 1/500ths. lol 5 inches
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#5
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Re: 500 hundreds of a inch
When someone says a 500th of an inch i think in decimal form, so In his case it would be .0500 which is 1/20 of an inch
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#6
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Re: 500 hundreds of a inch
This isn't rocket science:
Last edited by Tristan Lall : 18-02-2005 at 00:31. |
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#7
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Re: 500 hundreds of a inch
Ugh.. stupid scientific notations.
0.050 or 50 thousandths, is larger than you can think, and may affect form fit or function a bit with robots being 3 feet wide. (If it is an overall chassis cross member dimension). But, to add to that, a standard dimensional tolerance is +/- .002 of an inch on the parts I make on CAD at work. (Small cable connectors about an inch long (or less) total.) Think: the connector at the end of the cable snake that invades your home and brings you your TV and cable modem services. About that size. Last edited by Elgin Clock : 18-02-2005 at 00:36. |
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#8
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Re: 500 hundreds of a inch
wow my math is off...haven't slept in 2 days...
1/20 is quite larger but .002 in microscopic ( 1/25.4 is 1 millimeter) what and where exactly did this error occur and is it just annoying or is it a problem? |
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#9
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Re: 500 hundreds of a inch
Quote:
Quote:
Let's see: Δd = d0αΔT; for a 28" piece of framing, α = 23 × 10-6°C-1 (we'll call it constant for small ΔT), at 20°C, in 6101 aluminum (the closest I could find to 6105, which is actually used in 80-20); Δd = (28)(23 × 10-6)(5) = 0.0032" So if Δd = 0.0032", we're dealing with as much thermal expansion as we have machining tolerance, merely in taking it from the unheated cargo trailer to the pit area. That's why I think 0.002" is crazy, for our purposes. |
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