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#1
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Re: Pressure physics problems
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Just a clarification. I seem to remember from my scuba (and a few other) classes) that overburden pressure increases of incompressible materials (e.g. pressure increases associated with increasing water depth) is linear. So in the example cited above, would it not be that 1 liter of compressed air at 100 feet will expand to 2 liters at 66 feet, and 3 liters at 33 feet, and 4 liters at the surface? -dave |
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#2
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Re: Pressure physics problems
I also have some scuba classes under the belt, and I agree with you Dave, but I believe that he may have just misstated. I think he may have just meant 33 ft higher than 100, or 66ft.
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#3
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Re: Pressure physics problems
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I stand by my numbers... 1 atmosphere at sea level 2 atmospheres at 33 ft 3 atmospheres at 66 ft 4 atmospheres at 99 ft PV=nRT and, assuming that nRT is a constant, P and V are complementary (have an inverse relationship). The pressure at 33 ft is 1/2 of the pressure at 99 ft so that the volume in 2X the volume at 99 ft. Likewise, the pressure at sea level is 1/4 of the pressure at 99 ft such that the volume at sea level will be 4X the volume at 99 ft and 2X the volume at 33 ft. Like I said, the greatest danger is the last 10 feet. The esophagus is a very powerful muscle. Holding your breath in that last segment of an ascent will severely damage the lung tissues... Regards, Mike |
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#4
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Re: Pressure physics problems
Because I had two very learned men question my numbers, I went back to the physics book (see attachment).
Note that the plot of figure 17-4 (page 375 of Physics, 3rd edition, Halliday & Resnick, 1978) shows a linear (constant) P versus Y graph for depths below sea level. Mike |
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#5
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Re: Pressure physics problems
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