impossible statements

Michael Hill · #1 07-08-2005, 00:32

A + A - 2A = A + A - 2A (both members are identical)
A + (A - 2A) = (A + A) - 2A (associative property)
A + (-A) = (2A) - 2A (simplify contents of parentheses)
A - A = 2A - 2A
1(A - A) = 2A - 2A (factoring)
1(A - A) = 2(A - A) (factoring again)
1(A - A)/(A - A) = 2(A - A)/(A - A) (divide both sides by the quantity)
1 = 2

Error...can't divide by 0

mechanicalbrain · #2 08-08-2005, 11:14

Quote:

Originally Posted by Michael Hill

A + A - 2A = A + A - 2A (both members are identical)
A + (A - 2A) = (A + A) - 2A (associative property)
A + (-A) = (2A) - 2A (simplify contents of parentheses)
A - A = 2A - 2A
1(A - A) = 2A - 2A (factoring)
1(A - A) = 2(A - A) (factoring again)
1(A - A)/(A - A) = 2(A - A)/(A - A) (divide both sides by the quantity)
1 = 2

Error...can't divide by 0

How about 1(A-A)=2(A-A) can automattically be factored out because even if they didn't equal zero which they still are automatically factored out of the equation.

Greg Marra · #3 08-08-2005, 11:31

Quote:

Originally Posted by mechanicalbrain

How about 1(A-A)=2(A-A) can automattically be factored out because even if they didn't equal zero which they still are automatically factored out of the equation.

A - A = 2A - 2A

This step is already 0 = 0.

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