impossible statements

[Alan Anderson]

Originally Posted by Alan Anderson

".9999 continuing" is equal to 1.

Originally Posted by sanddrag

How do you figure? You are always going to have that really small (but existant) 0.00000...00001 left over. I see 0.999 continuing as approaching 1 but I am inclined to think it never actually gets there.

Your position is based on the false impression that the 9s eventually run out, leaving a bit left unaccounted for. They don't; that's what repeating decimals are all about.

Figuring it is easy:

       x = 0.9999...
     10x = 9.9999...
 10x - x = 9.9999... - 0.9999...
      9x = 9
       x = 1

See also http://en.wikipedia.org/wiki/Recurri..._of_0.99999... for other ways to demonstrate it.

[jdiwnab]

Originally Posted by Alan Anderson

Your position is based on the false impression that the 9s eventually run out, leaving a bit left unaccounted for. They don't; that's what repeating decimals are all about.

It is also similer to Limit of x as x approches 1. This isn't what is x when x is one, but you could treat it like that because x can be 1. you are so close to one that it might as well be one