Calculus Query

[David Guzman]

I might be wrong but:

f(x)=1
f'(x)=0
f(x)^-1=0/1=0

EDIT: OK, I am wrong

[Manoel]

Originally Posted by David Guzman

I might be wrong but:

f(x)=1
f'(x)=0
f(x)^-1=0/1=0

EDIT:
If you're considering the reciprocal, then 1/1 is not equal to 0.
If you're considering the inverse function, then I didn't understand what you tried to do.

f(x)^-1 is a poor notation because it usually refers to the inverse of a function but can also be mistaken for the reciprocal of the function.