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Re: Calculus Query
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Originally Posted by Manoel
Well, you didn't read the question with enough attention. Phrontist wants a function such that its derivative is equal to its inverse, not the function itself.
No, not at all. My previous example of y = x^2 would not be a function if you were correct. You described a bijective function, but there are also injective and, the ones that disproves you, surjective functions.
Yeah, that is correct if you disregard the derivative part of the problem. |
but you can only actually call it a function if its 1-1 in theory...
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20-10-2005, 19:42
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