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Originally Posted by Richard
and a few more batteries. A rough estimate goes like this: to accelerate a 120# 'foolhardy payload' to 40 MPH exit velocity at 13 ft launcher height would require about 500 lbf thrust for about half a second. Assuming 50% conversion efficiency from the battery, you'd need about 40 kW electrical power during that split-second. Since our 12V batteries can only deliver about 200 peak amperes, you'd need about 16 of them to do the job.
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Nah, it works on compressed air. They'd just have to tweak the pnumatics rules.
You know you are addicted to FIRST when you have trouble describing it because you realize it truly is way more than just a robotics competetion. - vivek16 [more] 
17-05-2006, 15:24
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