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#4
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Re: incrementing
i++ is shorthand for i = i + 1 since incrementing by one is such a common task in programming. Similarly i-- is the same as i = i -1. If you want to add or subtract something different then you have to use the long version as in i = i + 3.
Not many people realize you can also go ++i and --i which is subtly different. In most cases the end effect is the same but not always. With ++i (prefixed) the value is computed before the expression is evaluated. The postfix version i++ is the opposite where the value is computed AFTER the expression is evaluated. This doesn't make any difference if you just go: i++; or ++i; However if you try: m = ((++i)*(j++)/5; i will increment by 1 BEFORE the rest of the expression is evaluated. j will be incremented AFTER the expression is evaluated. Good luck! |
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