Rounding numbers

[neilsonster]

Ohh I see. Actually, this line:

time_i = ((i * 262) / 10000);

performs integer division, since time_i is an integer (you declared it as one). If you had declared time_i as a float/double, then this would give you a floating point number.

So after that line above, time_i is assigned 0 until i > 38 (i*262/10000 = i*0.0262 < 1, but since we have an integer it truncates the decimal part and gives you 0). For 38 <= i <= 76, time_i will be assigned 1 (you will have 1.***, and the decimal part will be removed). For 77 <= i <= 152, time_i = 2, and so on.

[teh_pwnerer795]

Originally Posted by neilsonster

Ohh I see. Actually, this line:

time_i = ((i * 262) / 10000);

performs integer division, since time_i is an integer (you declared it as one). If you had declared time_i as a float/double, then this would give you a floating point number.

So after that line above, time_i is assigned 0 until i > 38 (i*262/10000 = i*0.0262 < 1, but since we have an integer it truncates the decimal part and gives you 0). For 38 <= i <= 76, time_i will be assigned 1 (you will have 1.***, and the decimal part will be removed). For 77 <= i <= 152, time_i = 2, and so on.

Awesome thanxs alot .. makes more sense now