2 Cmucams?

[Alex G]

Technically, he is right. in an UART, each byte is 10 bits (1 start, 8 data, 1 stop). running at 115200 continuously gives 115200/ 10 * 2 interrupts / second for the recievers alone.
Of course, the PIC can handle that, considering that the cameras will not continuously send data, however, a few thousand interrupts per second will be generated.

[Tom Bottiglieri]

Originally Posted by Alex G

Technically, he is right. in an UART, each byte is 10 bits (1 start, 8 data, 1 stop). running at 115200 continuously gives 115200/ 10 * 2 interrupts / second for the recievers alone.
Of course, the PIC can handle that, considering that the cameras will not continuously send data, however, a few thousand interrupts per second will be generated.

The UART only triggers interrupts when it a packet hits on the Rx side. The CMU cam only puts out a few hundred interrupts per second.

[Kevin Watson]

Originally Posted by Alex G

Technically, he is right. in an UART, each byte is 10 bits (1 start, 8 data, 1 stop). running at 115200 continuously gives 115200/ 10 * 2 interrupts / second for the recievers alone.
Of course, the PIC can handle that, considering that the cameras will not continuously send data, however, a few thousand interrupts per second will be generated.

Okay, whatever

-Kevin

[Mike Betts]

All,

While we did not run 2 cameras, in 2005 we moved the camera to port 1 (programming port) and installed a SMiRF on port 2 to enhance code development.

We had no problems with interrupt overhead.

Regards,

Mike

[Alex G]

Originally Posted by Kevin Watson

Okay, whatever

-Kevin

We can choose to argue about the details, but the point that we agree on is that the Robot Controller can easily handle 2 CMU Cam's with your code.

[Kevin Watson]

Originally Posted by Alex G

We can choose to argue about the details...

I don't choose to argue about anything. I'm right and you're wrong. The serial data from the camera generates just over one hundred interrupts per second, not "a few thousand" and certainly not "11520".

-Kevin

[Alex G]

Originally Posted by Kevin Watson

I don't choose to argue about anything. I'm right and you're wrong. The serial data from the camera generates just over one hundred interrupts per second, not "a few thousand" and certainly not "11520".

-Kevin

You're right. I believed that the data packets were larger, but after checking the code carefully I found that I was wrong. Sorry if I seemed too jumpy.