Delay Function

[Anime-niac_2.9]

i've thought about it before, and it turns out something like bear24rw's idea.

int counter=0;

void User_Autonomous_Code(void)
{
  static unsigned int i;
  const float delay = 100;
  int counter, int limit=(delay*1000)*26.4;

  for(counter=0, counter<limit, counter++)
  {
  }
}

not necessarilly a function, but the interrupt code here (the for loop) should work. all you have to do if place the for loop whereever you want it

[bear24rw]

Originally Posted by Anime-niac_2.9

i've thought about it before, and it turns out something like bear24rw's idea.

int counter=0;

void User_Autonomous_Code(void)
{
  static unsigned int i;
  const float delay = 100;
  int counter, int limit=(delay*1000)*26.4;

  for(counter=0, counter<limit, counter++)
  {
  }
}

not necessarilly a function, but the interrupt code here (the for loop) should work. all you have to do if place the for loop whereever you want it

You need to be carefull with that loop, you need to call putdata and getdata every so often so the master processor doesnt shut down.. i forget what the actual timeout is but its not very long...

[TimCraig]

Originally Posted by Anime-niac_2.9

  const float delay = 100;
  int counter, int limit=(delay*1000)*26.4;

You do realize that the range for an int is -32,768 to +32,767?