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Unread 03-12-2007, 22:20
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Re: Mecanum Drive - Help

With a mecanum drivetrain is driving sideways (along the Y axis below), there are four force vectors (one from each wheel) directed at 45 degree angles:



The Y components of the force vectors make the robot move in the Y direction, and are each equal to sin(45)*F=0.707*F. The X components, which are also equal to .707*F, cancel each other out.

Therefore, the robot will have .707 the force driving its sideways movement as it will driving its forward movement.
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