problem with printing float

[Mark McLeod]

Here's an another alternative with just a little manipulation. You can turn something such as this into a utility function.

#define ACCURACY 1000  //How many decimal places are important to you
float f;
int i, i2;   // Might need to be longs if you have a lot of significant digits
 
f = 245.56;
 
/* Print float value */ 
i = (int) f;
i2 = (int) ((f-i)*ACCURACY);
printf("f = %d.%03d \r", i, i2); //e.g., f = 245.559