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The game starts, we learn, the game changes, we learn some more, the game changes again, we learn even more . . . - Bill Moore [more] |
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The game starts, we learn, the game changes, we learn some more, the game changes again, we learn even more . . . - Bill Moore [more] |
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#3
28-12-2008, 20:04
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Re: Some physics/math help
The page says, "There is a change of 1 mile for every 2 feet per second (fps) change in velocity when you are below a 500-mile altitude above the Earth." Sorry if I wasn't clear. I didn't mean they actually gave me two ratios.
I think it's much easier than it is made out to be, and others have mentioned that using that exact equation isn't even necessary. At the moment, I'm just stumped on the velocities. EDIT: Delta-V, change in velocity, is defined as (Vf-Vo), correct? If so, would Delta-V or the 'a' in the above mentioned formula be the given ratio? Last edited by ParkerF : 28-12-2008 at 20:12. Reason: Small thought. 
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