More friction questions

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11-01-2009, 17:38

writchie

Engineering Mentor

AKA: Wally Ritchie

FRC #2152 (Team Daytona)

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Re: More friction questions

Quote:

Originally Posted by Woody1458

We did a few rover wheel robot tests today and based on what I saw I am puzzled. It appeared that a lighter robot would accelerate faster then a heavy robot. Lets see if I can throw out some formulas

Heavier
533.8 N (120 lbs) (54.47 kg on earth) robot
Ff= µ • Fn
x = .05 • 533.8
x= 26.69 N
a=F/m
.4899 m/s^2 = 26.69 N / 54.47 kg

Lighter
400.3 N (90 lbs) (40.82 kg on earth) robot

40.82 * 9.8 = 400.03

to 4 digits this rounds to 400.0 not 400.3

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