12.75:1 enough? - Chief Delphi

12-01-2009, 11:23

DMetalKong DMetalKong is offline

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AKA: David K.

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12.75:1 enough?

Okay, I was working with some numbers and this is what I came up with for a 2 CIM drive (1 driving each side of the robot).

Torque supplied by 1 CIM at peak efficiency = 0.48 N m = 4.25 lbf in.
Torque supplied by 2 CIMs = 4.25 * 2 = 8.5 lbf in.

Max. Frictional Force = [150 lbf (robot) + 40 lbf (trailer)] * 0.2 (rounding the COF up quite a bit) = 38 lbf.

Max. Torque = 38 lbf * 3 in (wheel radius) = 114 lbf in.

Torque needed/Torque provided = 114/8.5 = 13.4.

A toughbox provides a 12.75:1 reduction. Does anyone think that this will be sufficient for powering a robot?

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