Quick release

[Chris Fultz]

Originally Posted by Hastypickle

Sure.
I was thinking maybe the pneumatic actuator could be used, but I don't know how much force that would be able to hold.

at 60 psi, a 3/4" diameter cylinder has 26.5 pounds of force in the extend direction and 23.5 in the retract direction. If that is not enough, you can step up to a larger diameter.

the equation is f=pa, or force = pressure x area.
for the example above, in the extend direction it is

f = 60 pounds / inch^2 x 3.14 (.375^2) = 26.49 pounds

for the retract, you have to subtract the area of the internal rod,
so the effective area is reduced (0.25 diameter = .125 radius)

f = 60 pounds / inch^2 x (3.14 (.375^2) - 3.14 (.125^2)) = 23.55 pounds.