Confusing rule: Finale Configuration

[jackshamu]

So a robot with length 38 would be able to reach 23 inches away from the longest side in a straight line perpendicular from the center before violating the rule?

I got 23 through
38/2=19 half the lenght
84/2=42 half the diameter
42-19=23 half the diameter minus half the lenght

it would also be able to reach a max of 28 inches from the width if its width is 28 inches

[EricH]

Originally Posted by jackshamu

So a robot with length 38 would be able to reach 23 inches away from the longest side in a straight line perpendicular from the center before violating the rule?

I got 23 through
38/2=19 half the lenght
84/2=42 half the diameter
42-19=23 half the diameter minus half the lenght

If your robot is centered on the cylinder, yes. Note, however, that you are wasting a lot of reach doing this.

A longer-reaching, though harder to work with, geometry is this: Take the back side of the robot and place it so the corners are on the circle (the base of the cylinder). This forms a secant of 28". Now run a line right down the middle of the robot to the far side of the circle. The length of that line is the reach you have to work with.

[jujuninja]

We had to have a guy in PHD physics to help us out the best way i could think from him said is. Take a pop can put it on a cd or dvd and you can tilt it in different but u cant leave the parameters of the disk.

[EricH]

Originally Posted by jujuninja

We had to have a guy in PHD physics to help us out the best way i could think from him said is. Take a pop can put it on a cd or dvd and you can tilt it in different but u cant leave the parameters of the disk.

But it's defined relative to the robot (<R10>), so tilt the CD with the can.