Camera Target Dimensions

[pribusin]

at http://www.usfirst.org/roboticsprogr....aspx?id=16097 are 4 .zip files with a number of arena drawings etc. None of these contain GE-10059.

I drew 3 concentric circles each 4" wide and the outer white circle measuring 42" in dia. and it looks nothing like in the game field animation or the arena diagrams in the manual.

[DanDon]

Originally Posted by pribusin

at http://www.usfirst.org/roboticsprogr....aspx?id=16097 are 4 .zip files with a number of arena drawings etc. None of these contain GE-10059.

I drew 3 concentric circles each 4" wide and the outer white circle measuring 42" in dia. and it looks nothing like in the game field animation or the arena diagrams in the manual.

You have the 4" widths measuring from the outside? so the outer white circle would be 42" dia., the black would be 38" dia., and the inner white would be 34" dia., if I recall correctly.

[pribusin]

But don't forget you have two widths of 4" per circle that you have to subtract to get the inner diameter (ID). If you draw a 42" OD circle that is 4" wide your ID is: 42"-(2x4")=34". That gives you a 4" wide band as a circle with an OD of 42". That is the white ring. The black ring would then be 34" OD and 26" ID. The innermost white circle would end up being 26" OD and 18" ID. Is my thinking wrong on this???

BTW, we posted on the USFIRST forum inquiring about the GE-10059 document. Hopefully that file will clear things up.

[bobmonkey836]

the included GE-10063.pptx has what looks to be a diameter of 38 inches for the rings...

the whole thing comes out as 42 inches across though.