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Unread 17-01-2010, 14:46
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Re: pic: 2010 window motor winch

Quote:
Originally Posted by rsisk View Post
I have to agree with Tom about the great explanation from Joe, but, show some mercy on a software guy and explain the formula use to calculate the 54W below.

TIA
Here's one way I came up with 54W:


120lbf * 3ft = 488 J (Work = Force*Distance, there's a conversion factor from lbf-ft to J in here as well. Google Calculator did this conversion for me)
488J/ 10s = 48.8W (Power = Work/Time)
48.8W / .9 = 54 W (Gearbox efficiency)

From what I remember reading here and erring on the side of caution I would use 80% as the gearbox efficiency yielding 61W of power necessary.

Also be careful using 120lb as a weight. A full 120lb robot this year could end up at over 150lb after adding battery and bumpers. Using 150lb and 80% efficiency you need about 76W of power to complete the lift in that time.
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