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Re: Drive Sizing 101
1.) FP has a Torque of 0.45 Nm, which is equal to 3.982 in*lbs.
Code:
3.982 in*lbs x 1,500(gear ratio) = 5,973 in*lbs Code:
5,973 in*lbs / 150 lbs (weight of Robot) = 39.82 inches Code:
15,600 RPM / 1,500 (gear ratio) = 10.4 RPM Code:
10.4 RPM / 60 seconds = 0.173 RPS Code:
0.173 RPS * 5 Seconds = 0.867 of a Revolution = 312 degrees That is my guess. -Clinton- |
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