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Unread 04-02-2010, 07:00
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Re: 1771's Jaguars

As an exercise, measure the resistance across the leads of a CIM. I measured between .4 and .6 ohms. The voltage of a fully charged battery can be from 12-13 volts.

Applying Ohm's law, we know that (in simple circuit) I=V/R, so at worst case (highest current), we would have 13V/.4ohms, giving you 32.5 Amps. At best case, 12V/.6ohms gives you 20 amps.

As I said, I saw max currents in the low 30 amp range. If you would likem perform your own experiment.

Remember, take everything you hear (or read) with a grain of salt, and to everything you say, add a grain of sugar.
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