Go to Post It's funny how many things learnt in Physics class at school I am able to apply to FRC. - pilleya [more]
Home
Go Back   Chief Delphi > Technical > Technical Discussion
CD-Media   CD-Spy  
portal register members calendar search Today's Posts Mark Forums Read FAQ rules

 
 
 
Thread Tools Rate Thread Display Modes
Prev Previous Post   Next Post Next
  #2   Spotlight this post!  
Unread 10-02-2010, 09:53
lbarger's Avatar
lbarger lbarger is offline
Senior LRI NC District
AKA: Lee Barger
FRC #0587 (The Hedgehogs)
Team Role: Mentor
 
Join Date: Dec 2005
Rookie Year: 2001
Location: Hillsborough, NC
Posts: 81
lbarger has much to be proud oflbarger has much to be proud oflbarger has much to be proud oflbarger has much to be proud oflbarger has much to be proud oflbarger has much to be proud oflbarger has much to be proud oflbarger has much to be proud oflbarger has much to be proud of
Re: kicker

Quote:
Originally Posted by rytcd View Post
hey, would a pneumatic pendulum style kicker be more powerful than a straight horizontal pneumatic punch? also, might it be better to use a kicker with a smaller surface area?
That is a tough question to answer as there are many variables. Desired ball velocity, cylinder size, total air flow (Cv of valve or valves), mass of the kicker, etc. all interplay with each other.

With unlimited air flow, a horizontal punch would deliver the higher force. However, you may not need to deliver 100 pounds of force to the ball to get it to move the way you want. Speed may be more critical than force. If so, then the pendulum will give you more speed at the cost of some force.

Here are a few formulas:
1) (1/2)*acceleration*time^2 = Distance (assuming uniform acceleration and initial velocity of zero)
2) acceleration*time = velocity

Rewriting the second equation you get acceleration = velocity/time
Substituting that into the first equation and simplifying you get...
(1/2)*velocity*time = Distance
Rearranging you get to
3) Time = 2*Distance/Velocity

What speed do you want the ball to travel? (I'll assume 15 ft/s)
How much distance do you have to accelerate it? (Assume 3" inside frame + 3" under bumpers = 6" or 0.5 ft.

Plugging these numbers into equation 3 you find that time of acceleration should be close to 0.05 seconds. Putting this back into equation 2 and solving for acceleration you get acceleration = 15(ft/s)/0.05s or 300ft/s^2.

Divide the acceleration by 32.2 ft/s^2 (force of gravity) and you find the acceleration is 9.3G. Now the weight of a soccer ball is about 0.95 pounds. But to accelerate at 9.3G you have to multiply (0.95*9.3) and you find the force to accelerate the ball to 15 ft/s in 0.5 ft is averaged out to be just 8.9 pounds of force.

Of course I pulled the velocity off the top of my head and you may want to use less total distance. Actually, it would be safe to assume the ball does not stay in contact for the full stroke.

So use the equations, not the numbers and good luck!
 


Thread Tools
Display Modes Rate This Thread
Rate This Thread:

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

vB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Forum Jump

Similar Threads
Thread Thread Starter Forum Replies Last Post
Team 61 Kicker KC1AJT Robot Showcase 0 02-02-2010 18:30
Kicker Help? infocus Technical Discussion 23 30-01-2010 15:28
2495's Kicker Brandon_L Robot Showcase 8 28-01-2010 20:16
Hybrid Kicker falconmaster General Forum 15 20-01-2010 14:27


All times are GMT -5. The time now is 01:27.

The Chief Delphi Forums are sponsored by Innovation First International, Inc.


Powered by vBulletin® Version 3.6.4
Copyright ©2000 - 2017, Jelsoft Enterprises Ltd.
Copyright © Chief Delphi