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Re: Measuring resistance using analog breakout
Easiest to wire would be a voltage divider between a known resistance and your sensor. Think of it like your potentiometer, only with a variable resistance between +5 and GND.
Wiring would be so: Sensor between SIG and GND Known resistor between +5V and SIG You'd get a varying voltage on your SIG equal to the following: R - constant known resistance r - variable sensor resistance V = 5 * r / (r + R) If you pick an R value about 5-10 times the maximum value of r, you'll end up with a moderately linear signal, if rather small. Other options are various amplifier and/or transistor circuits which will all be a bit complicated. |
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