High score of the season

[Lil' Lavery]

Originally Posted by Formerly Famous

Maybe it's not traction you need... F=m*a So would a robot that weighs around 110 pounds(maybe 120, which would put it 130 with the battery) so with enough acceleration, (driving right under the tunnel) couldn't they pop it out, and then push them backwards enough to disrupt the strategy? (Not saying I would recommend this, I'm just saying it's possible.)

Just my $.02

Keep in mind that 469 is able to apply a force in opposite direction that this robot is pushing. Your acceleration (and therefor your force in the "pushing axis") is hinged upon the force you apply to the floor (very same F=ma equation you mentioned). That force is limited by the friction that the robot can generate, which is governed by the coefficient of friction of the wheels and the normal force of the robot. Because of 469's mechanism, their normal force is going to be much larger than the pushing robot, and thus they're going to have a much higher "pushing force" than the robot trying to dislodge them. And on top of that they have the forces being applied to them by the tower.

I don't think you'll see 469 budge.