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 ...and part of being Graciously Professional is knowing what your job is and how to perform the duties of it accurately. - jamie_1930 [more] |
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| ...and part of being Graciously Professional is knowing what your job is and how to perform the duties of it accurately. - jamie_1930 [more] |
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#8
16-11-2001, 19:38
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I agree with Ken's answer (although i got it in a slightly different form)
S = (3*sqrt(3) + 2*sqrt(2))R = Ken's answer since 3*sqrt(3) = 6*Sin120 R = S / (3*sqrt(3) + 2*sqrt(2)) and BD = S * sqrt( (237 - 40*sqrt(6)) / 361) The solution for finding R in terms of S basically boils down to finding the sides of 3 right triangles for those who are looking for a hint. (Remember the special stuff about tangents to circles? yeah...) And to find BD, cosine law  Soo... do I win a prize too?  Anthony. Last edited by Anthony X. : 16-11-2001 at 19:50. 
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