How Do mecanum wheels handle the bumps?

[efoote868]

Originally Posted by Ether

Maybe, maybe not.

I was hoping to have a discussion of the forces/torques produced by mecanum wheels in motion after first obtaining some sort of general consensus concerning static analysis of mecanum wheels, but obtaining such consensus has proven quite a bit more problematic than anticipated.

Theoretical arguments and gedanken experiments have not been persuasive. When the season is over I hope to get my hands on some mecanum wheels and gather some additional test data. I would be delighted however if someone else beats me to it.


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This discussion might be better suited to a different thread.

[NyCityKId]

I've been looking into this locking mecanum design as seen here and i would like to know if anyone has found a way to make this or something similar work (in reference to the lockable rollers not the rotatable rollers). I would like to apply something like that our robot next year and I'm starting research early. anyway if anyone can help me understand this system your help would be greatly appreciated.

[Ether]

Originally Posted by fritzdejongh

If anyone's at the Minnesota regional later this week, we can draw some diagrams.

Did this ever happen ?


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[fritzdejongh]

Originally Posted by Ether

Did this ever happen ?


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Sorry, First Baron, at least I wasn't involved in any such discussion. It would probably be a good topic for the FIRST Robotics Conference or something.

[Basel A]

To resurrect the discussion here. As in the examples suggested, one standard wheels would have 10 lb. of torque. Doesn't it follow that 45 degree mechanums would apply 10 lb. of force at that 45 degree angle?

You've agreed that the mechanum has seperate and equal sideways and forward forces, and the disagreement is what the total force is, as well as each seperate force (which would each follow from the other).

Can we also agree that the total force is a seperate force*(sqrt)2?

I'd also like to resuggest the idea of 60 degree mechanums. It was suggested they would still have 10 lb. forward force, with a lesser sideways force. What if you mounted 30 degree mechanums perpendicularly? With the rollers at the same angle, shouldn't forces be the same? The constant 10 lb. forward force model wouldn't work if I'm correct.

I've taken only basic physics (I do understand vector math), so feel free to correct me if I'm way off here.

[Jared Russell]

Originally Posted by Basel A

To resurrect the discussion here. As in the examples suggested, one standard wheels would have 10 lb. of torque. Doesn't it follow that 45 degree mechanums would apply 10 lb. of force at that 45 degree angle?

You've agreed that the mechanum has seperate and equal sideways and forward forces, and the disagreement is what the total force is, as well as each seperate force (which would each follow from the other).

Can we also agree that the total force is a seperate force*(sqrt)2?

I'd also like to resuggest the idea of 60 degree mechanums. It was suggested they would still have 10 lb. forward force, with a lesser sideways force. What if you mounted 30 degree mechanums perpendicularly? With the rollers at the same angle, shouldn't forces be the same? The constant 10 lb. forward force model wouldn't work if I'm correct.

I've taken only basic physics (I do understand vector math), so feel free to correct me if I'm way off here.

Read this: http://www.chiefdelphi.com/media/papers/2385