Quote:
Originally Posted by kamocat
But check this out:
If I have my setpoint at 40A, and my proportional coefficient coefficient at 1, then it outputs 3.5 volts. (It also says my motor is drawing 2.25A at this low speed) Apparently, 1*(40-2.25) = 3.5 (Or rather, 3.5÷12 full power)
Does that mean that somewhere in here something's scaled incorrectly?
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Marshall -
Something in my head just jostled loose regarding this statement.
The PID loop uses the current sensor as an
input and gives duty cycle as an
output. Therefore, the style of analysis you were attempting does not work in this situation. Your example becomes:
% on time = scaling_factor * 1 * (40-2.5)
instead of
Amps = 1 * (40A-2.5A)
Every year, everyone reads too much into the hints given by Dave. - EricH [more] 
20-06-2010, 17:08
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