CIM Quiz 2

[Jared Russell]

Originally Posted by Tom Line

Ok. My first question is where did you get the specs for your impeller (is that provided by the manufacturer?).

Anyway: (apologies in advance - this is for 10.5 volts as that is all I had on my scratch pad from when I worked a similar problem before)

Cim @ 35 amps: .70 Nm torque, 230 W, 395 rad/s = 3770 rpm
Fish @ 35 amps: .260 Nm torque, 180 W, 686 rad/s = 6550 rpm

Total power, 230 W + 180 W = 410 W (assuming zero loss - real life I'd throw a 20% in here).

410 W= rpm^2 / 81500, rpm = 5780 rpm

3770 (cim) / 5780 = .65:1 or 1:1.53 for the cim.
6550 (fish) / 5780 = 1.13:1 for the fish.

Your request didn't specify the maximum amperage, so I assumed 35 to be safe for our 40 amp breakers. If taken at 12 volts these will be slight different. This is based on the free speed of the motors at 10.5 volts, but truthfully it shouldn't be /that/ far off from 12 volts.

I believe you are making the mistake of assuming the motors are providing their maximal mechanical power while spinning at their free speed.