Quote:
Originally Posted by beemgruem
For my drive train don't I need 2 victors for just 2 CIMs? Am I wrong? Why would I need 4?? And we are having 1 for our lifting actuator.. So that shows three? I am just lost for 2 CIMs for 4??
And also it is a good idea to just replace it.. I think I will use it..
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Rule of thumb: If it's a motor, it uses a Victor. If it's a piston (or a motor used like a piston), it uses a spike. So, two CIMs per side of the drive, that's four victors. I guess they have four motors for a hurdling device.
In your case, as described in this post, yes, you only need three. Add one per motor added later. (e.g. adding two CIMs to the drive takes your total to five.)
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