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Unread 04-20-2006, 09:31 AM
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Re: paper: 2006 Niagara FIRST Public Championship Scouting Database

Well from what I have seen the seed percentage is saying how much percentage of the competition you seeded higher than. Take for example 229. We seeded 6th at FLR.

Since there were 30 teams at FLR:

100% - (4(seed) / 30 (# of teams) * 100) = ~83%

the iner part gives you a the percentage of teams that did better than you. so just subtract that number from 100 and you get the number of teams you did better then.
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Unread 04-20-2006, 03:56 PM
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Re: paper: 2006 Niagara FIRST Public Championship Scouting Database

Quote:
Originally Posted by Peter Matteson
Karthik,
Another mentor and I were trying to figure out how you calculate the value for seed %. We weren't able to quite figure it out. Can you explain that one?
Pete
Pete,

Let t = number of teams at the regional
Let s = the team's seed

Seed % = (t - s + 1)/t
= 1 - ((s-1)/t)

As Tim mentioned, this calculation produces the percentage of teams a given team was seeded higher than.
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Unread 04-20-2006, 07:26 PM
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Re: paper: 2006 Niagara FIRST Public Championship Scouting Database

Quote:
Originally Posted by Karthik

Let t = number of teams at the regional
Let s = the team's seed

Seed % = (t - s + 1)/t
[font=Courier New] = 1 - ((s-1)/t)
Ok, this post embodies the reason that Karthik has a degree in math and the rest of us don't...
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