|
Lots of Wheels and F = u x N
Posted by Ernie P at 1/25/2001 9:41 AM EST
Engineer on team #548, RoboStangs, from Northville High School and Robert Bosch.
Hi all you gearheads out there,
I'm an RF electronics guy ... so all this traction stuff is just another exercise in vector analysis to me. My old physics classes told me that F = u x N, or propulsion force equals the coefficient of friction times the force normal to the surface.
So, why does everyone want to add 356,215,492 wheels to the robot???? When you add another wheel, the force is distributed so your N is reduced by 50% .... net result is no increase in propulsion force. I can see for real trucks that they need to distribute the load on roads and may be happier on soft surfaces, but why are more wheels better for us???
Your words of wisdom to enlighten my meager knowledge will be accepted as a ray of light in my void of ignorant darkness.
Thanx, Ernie P
__________________
This message was archived from an earlier forum system. Some information may have been left out. Start new discussion in the current forums, and refer back to these threads when necessary.
|
Look for metal shavings in a pwm port; that's caused us to crash plenty of times. - Gary Dillard [more] 
Similar Threads
Threaded Mode