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#1
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Statistics Quiz#1
OK, here's an off-season challenge for the stats gurus here on CD: A computer equipped with a quantum noise random number generator is programmed to perform the following experiment: It flips a biased coin 2000 times and records the number of heads for that experiment. The coin is biased so that it is twice as likely to come up tails than heads for any given flip. If the computer were to perform 100 of these experiments, what is the probability that more than 59 of those 100 experiments would each have fewer than 672 heads? Last edited by Ether : 30-12-2013 at 01:38. |
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#2
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Re: Statistics Quiz#1
You're retired, right? Otherwise you'd never have the time to come up with such devious (and interesting) problems.
Anyway, you can also look at the problem as having a 3 sided coin, and we're only interested in side B, not sides A or C. I got a C in Statistics. 34 years ago. ![]() |
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#3
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Re: Statistics Quiz#1
Yeah, retired. I highly recommend it
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Last edited by Ether : 30-12-2013 at 19:12. |
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#4
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Re: Statistics Quiz#1
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Follow Ether's lead on this: concentrate on the physics while you are young, and save the statistics for your later career (or retirement). Too many engineers today rely on statistical inference to make decisions, when a relatively small dose of physics would have provided the required insight much more directly. |
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Re: Statistics Quiz#1
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#6
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Re: Statistics Quiz#1
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Also, I feel bad that I ignored the mathematical analysis and my answer to the original question is "a tad less than 50%". Last edited by s_forbes : 30-12-2013 at 21:48. |
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#7
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Re: Statistics Quiz#1
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(I'd say statistics are extremely useful in quality management for high-volume production, in processes that have already been well-characterized and refined. But that's probably not the scenario being criticized.) |
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#8
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Re: Statistics Quiz#1
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#9
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Re: Statistics Quiz#1
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-- quantum models for very small scale material properties - as Michael Hill pointed out above, this is a special case for which statistics is an indispensible part of physics, -- developing strategies for playing games of chance, -- detection and ranging methods to extract useful signals in the presence of background noise, and -- optimizing large scale serial manufacturing processes by isolating defect causes that arise due to variation of many potentially interacting factors. In each of these situations, the challenging aspect is random variation in the observed data. However, there are many more engineering situations in which statistical inference is not the best tool. The scenario I was criticizing above arises when an engineer tries to use statistical inference to understand patterns in observed data that are not random at all, but instead are based on physical principles the the engineer has failed to recognize -- in such situations the challenge is not random variation, it is ignorance. Ignorance cannot be overcome by statistical inference. |
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#10
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Re: Statistics Quiz#1
P(B(2000,1/3)<672) = .5929
P(B(100,.5929)>59) = .4855 Is this a rounding error of 1/2? |
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#11
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Re: Statistics Quiz#1
Your approach looks correct, but your result for P(B(2000,1/3)<672) looks a bit off. What app did you use to compute the value .5929?
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#12
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Re: Statistics Quiz#1
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P(B(2000,1/3)<672) = .589957 P(B(100,.589957)>59) = .4616 No? |
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#13
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Re: Statistics Quiz#1
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As in your first post, the second computation is correct, but the first is off a bit. I suspect the web sites you are using implement algorithms which are not accurate for larger numbers. But hey, you understood how to solve the problem. Reps to you! PS: I ran the numbers in Python, Octave, Scilab, and Maxima and they all agreed with each other out to ~12 sigfigs. If anyone reading has access to Matlab and/or R, could you please post the result for: p1 = binocdf(671,2000,1/3) |
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#14
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Re: Statistics Quiz#1
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Code:
p1 =
0.5916
Code:
p1 = 0.591634715653171 |
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#15
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Re: Statistics Quiz#1
Thanks Ryan.
If anybody has access to R, Mathematica, MathCAD, or Maple, would you please post the value computed for p1? I'm investigating which numerical package gives the most accurate answer. |
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