Break-Even Point to Cost/Revenue problem

edure · #1 01-09-2007, 14:18

Anyone has any suggestion on solving this problem for x?
It's a break even point to a cost and revenue problem.

5.5 sqrt(x) + 10000 = 3.29x where x>o

thanks

Kevin Sevcik · #2 01-09-2007, 14:58

put everything on the right side of the equation and treat it as a quadratic. If it helps you come to grips with it better, make yourself a dummy variable "a". Let a=sqrt(x). So a^2 = x. And then it's a straight forward quadratic.

edure · #3 01-09-2007, 15:54

thanks for the suggestion kevin. very clever, but it didnt work. i ended up w/ x~54.3.
the proposed solution is x~3133.

Kevin Sevcik · #4 01-09-2007, 16:13

I refuse to be wrong on my birthday. Also, I ran the numbers and got a = sqrt(x) = 55.63. So x = 3095.6. Mostly, you forgot that that quadratic solves for sqrt(x) so you need to square the answer to actually get x.

edure · #5 01-09-2007, 16:45

YOU'RE THE MAN KEVIN, that's it!!!!
many thanks....happy birthday!

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