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Help wiring potentiometer-to-Analog port
I picked up a 10k pot cheap at an electronics shop (for testing only) and am trying to connect it to the Analog port. The pot is a slider-style and has no markings on it. If anyone can help me figure out how to wire it I would be very appreciative.
There are 3 posts on this slider. On one end there is a silver post (call it "A") On the other end there is a silver post (say "B") and a gold post (call it "C"). Kind of like this (I'll try to "draw" it - pretend the dashes aren't there and that's space between the legs) |----------------------------|-------| |----------------------------|-------| A--------------------------- C-------B slvr------------------------gold-----slvr A and B are on one side ("front" as pictured above) and C is on the other side ("back"). When I put a meter from A to B I get about 10k ohms regardless of the position of the handle. When I put a meter from A to C I get close to 0 ohms when the handle is on the left and nearly 10k ohms when the handle is on the right (and about 5k ohms when it's in the middle) When I put a meter from C to B I get nearly 10k ohms when the handle is on the left and close to zero ohms when the handle is on the right (just the opposite of the A to C measurement) The way I read the diagram I should wire A & B to Red & Black (+5V & Ground) and wire C to White. Switching A & B around will only change which end of the pot gives me +5V vs. 0V. Is this right? Can anyone verify or correct this? Thanks Last edited by kylehager : 17-01-2008 at 05:03. Reason: can't get the drawing to look right |
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