VEX Returns Robotics to Disney World

[Rick TYler]

This announcement was made on the VEX forum today:

Greetings VEX Teams,

That's right. We are thrilled to announce a new event is being added to the annual competition schedule - the VEX Robotics All-Star Challenge at Disney's Wide World of Sports® Complex Presented by NASA, iRobot, EMC, Autodesk and the WALT DISNEY WORLD® Resort. The tournament will be held November 12-14, 2009 at the WALT DISNEY WORLD® Resort near Orlando, Florida.

A multi-year agreement has been reached with the WALT DISNEY WORLD® Resort to host the VEX Robotics All-Star Challenge each fall at Disney's Wide World of Sports® Complex. The top teams from the VEX Robotics World Championship will earn special invitations to this event each year. The All-Star Challenge will be open to any teams from around the world who wish to participate and test themselves against the best of the best from the previous season in the new game for the current season (2009/2010-Clean Sweep).

The VEX Robotics All-Star Challenge at Disney's Wide World of Sports® Complex will also be a qualifier for the VEX Robotics Competition World Championship, with the top teams earning an automatic spot. The event is now posted and open for registration, but space is limited.

Entry Fee: $250 per Team
Disney Hotel three night package:
Quad Room: $295 per person
Triple Room: $320 per person
Double Room: $363 per person
Single Room: $494 per person
Airport to Hotel Transportation: Included
Hotel to Event Transportation: Included
Park Passes: Included
Free entry into the Disney¹s Wide World of Sports® Complex: Included

You can visit the All-Star Challenge event page at Robotevents.com to register and for more detailed information. More hotel package details and an online registration site to reserve your hotel packages will be posted in the next couple of weeks on Robotevents.com.

We're very excited about the new partnership and can't wait to see the level of competition at this new premier VEX Robotics "All-Star" event each fall.