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Motor Power Calculations
First, a couple of disclaimers:
With that being said -------------------------------------------------------------------- Let's say that you want to have a drivetrain with 4 CIM motors and 4 RS-550 motors. The max power of the CIM is 340 W, and the max power of the RS-550 is 254 W. The total max power is Code:
4 * 340 W + 4 * 254 W = 2,376 W Code:
2,376 W * 0.8 = 1900 W = 1406 ft-lb/s Power = Torque * Angular Velocity, so Angular Velocity = Power / Torque. Torque = Force * Distance. For 4in diameter (2in radius) wheels, the distance is 0.1667ft (2in). The force is equal to the Frictional force, which I'll say is Code:
Ff = u * Fn = 1.0 * 165lb = 165lb The torque is then Code:
165lb * 0.1667ft = 27.5ft-lb Code:
(1406 ft-lb/s) / (27.5 ft-lb) = 51.127 rad/s Code:
51.127 rad/sec * rev/(2pi rad) * 60 sec/min = 488 rpm The RS-550, which has a free rpm of 19300, should be geared down 19300/488 = 39.55:1. Also, the RS-550 could be geared down to the free speed of the CIM - 19300/5310 = 3.63:1 - and then the two inputs merged, and the final 10.88:1 reduction applied. Last edited by DMetalKong : 10-01-2011 at 13:21. |
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