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#1
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PID crossing 0
I am right now working on "unicorn drive" code, and I almost have all of it done.
I have one question: as I understand, PID's never cross 0 and go back to the max. since the crab pods being rotated are coaxial, they can and should cross 0 to making turning faster; I already have a "shortest distance; flip the wheel speed and lose 180 degrees from the setpoint if the distance is over 180 degrees. Is there an alternative to a PID that will let me cross 0 or a way to make the PID cross 0? or do i need to write my own algorithm to render that? |
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#2
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Re: PID crossing 0
I think I see what you're getting at, but if I've interpreted your question incorrectly, please clarify.
In the standard formulation of a PID controller, all three controllers (proportional, integral, derivative) use an error signal defined as Code:
<error> = <set point> - <measured> Code:
float computeError(float setPoint, float measurement) {
float err = setPoint - measurement;
err -= (2*M_PI) * rint(err / (2*M_PI));
return err;
}
The issue with this is you now have discontinuities in your error function, so you'll want to provide some sort of protection so your derivative term doesn't blow up (e.g. if your error signal jumps from -3.14 to +3.14, derr/dt ~= 6.28 / (0.0333 sec) = 188.4). --Ryan P.S. If someone needs helping converting into Java or LabVIEW (or Python or ...), let me know Last edited by RyanCahoon : 26-05-2011 at 04:30. |
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#3
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Re: PID crossing 0
By "cross zero" do you mean wrap phase? As in your number line goes 358, 359, 0, 1, 2?
There are wrap/unwrap phase VIs that might help you with this. Just be warned that they aren't psychic. |
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#4
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Re: PID crossing 0
thats what i meant.
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#5
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Re: PID crossing 0
Quote:
angle_error = target_angle - measured_angle; angle_error -= 360*floor(0.5+angle_error/360); then: setpoint = angle_error; process_variable = 0; OR setpoint = 0; process_variable = -angle_error; The disadvantage of the first approach is that the Derivative term will be disabled since the WPI Lib PIDs only look at the derivative of the process_variable. The disadvantage of the second approach is that, although the Derivative term will be active, it will respond to changes in BOTH the measured_angle as well as the target_angle, so be careful how you adjust it. Notice that the first two lines of code above (calculating the angle_error) calculate the shortest angle distance to the target. You need extra conditional logic only if you want to change the sign of wheel speed. See the discussion here. Last edited by Ether : 26-05-2011 at 09:44. |
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#6
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Re: PID crossing 0
Quote:
my concern is it going all the way around from say 0 to 7pi/4 as opposed to only moving a distance of pi/4. my only real knowedge of pid is you give it a setpiont and a process variable and it controls a motor within given range of outputs. a lot of the nuts and bolts i have yet to learn. |
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#7
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Re: PID crossing 0
Quote:
Quote:
For example, suppose your steering angle encoder ("measured_angle") reads 0 to 360 degrees clockwise, with zero being "straight ahead". Suppose your calculated desired steering angle ("target_angle") also is 0 to 360 degrees, again with 0 being straight ahead. Then let's do some example calculations: Example 1: measured_angle = 359 degrees target_angle = 2 degrees angle_error = target_angle - measured_angle = 2 - 359 = -357 degrees angle_error -= 360*floor(0.5+angle_error/360) = +3 degrees setpoint = angle_error = 3 degrees process_variable = 0 degrees In other words, the PID will try to rotate the steering clockwise 3 degrees, which is what you want. Example 2: measured_angle = 4 degrees target_angle = 354 degrees angle_error = target_angle - measured_angle = 354 - 4 = 350 degrees angle_error -= 360*floor(0.5+angle_error/360) = -10 degrees setpoint = angle_error = -10 degrees process_variable = 0 degrees In other words, the PID will try to rotate the steering counter-clockwise 10 degrees, which is what you want. Notice how, in each of the above examples, the code "angle_error -= 360*floor(0.5+angle_error/360)" calculates the shortest angle path (and the correct angle direction) from the measured_value to the target_value. Last edited by Ether : 26-05-2011 at 15:33. |
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#8
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Re: PID crossing 0
if what i am reading is correct, then:
i can use target-measured=setpoint; process =0 everything in the code is in radians. |
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#9
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Re: PID crossing 0
Quote:
If you leave that line out, you will get the following: Example 1: measured_angle = 359 degrees target_angle = 2 degrees angle_error = target_angle - measured_angle = 2 - 359 = -357 degrees setpoint = angle_error = -357 degrees process_variable = 0 degrees In other words, the PID will try to rotate the steering counter-clockwise 357 degrees, which is NOT what you want. Example 2: measured_angle = 4 degrees target_angle = 354 degrees angle_error = target_angle - measured_angle = 354 - 4 = 350 degrees setpoint = angle_error = 350 degrees process_variable = 0 degrees In other words, the PID will try to rotate the steering clockwise 350 degrees, which is NOT what you want. If you are using radians instead of degrees, then replace "angle_error -= 360*floor(0.5+angle_error/360)" with "angle_error -= 2pi*floor(0.5+angle_error/2pi)". |
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#10
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Re: PID crossing 0
i see... but what exactly do you mean by "floor"? never seen that math operation before.
edit- i see now... its the lowest integer function. however the equations doesn't work. did you mean somethign else? Last edited by ratdude747 : 26-05-2011 at 16:12. |
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#11
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Re: PID crossing 0
Quote:
Yes, it's part of the standard C library. For LabVIEW users, the calculation "angle_error -= 360*floor(0.5+angle_error/360)" can be coded as shown in the attachments to this post. Notice that it doesn't matter if your angles are from 0 to 360 or from -180 to +180. All that matters is that they are both zeroed at the same point and that they are both measured in the same direction. For example, let's re-do the Example2 calculation in this post, but with the calculated steering angle being from -180 degrees to +180 degrees instead of 0 to 360 degrees, to show that the exact same code can be used to give the proper result So, your steering angle encoder ("measured_angle") reads 0 to 360 degrees clockwise, with zero being "straight ahead". And your calculated desired steering angle ("target_angle") is -180 to +180 degrees, again with 0 being straight ahead. Example 2: measured_angle = 4 degrees target_angle = -6 degrees (instead of +354 degrees) angle_error = target_angle - measured_angle = -6 - 4 = -10 degrees angle_error -= 360*floor(0.5+angle_error/360) = -10 degrees (you still get -10 degrees, which is what you want) |
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#12
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Re: PID crossing 0
Quote:
Please post an example. Here's a complete C program. Compile and run it: Code:
#include <math.h>
#include <stdio.h>
void test(double target, double measured){
double angle_error;
printf("\n%12.3f target\n%12.3f measured\n",target,measured);
angle_error=target-measured;
angle_error -= 360*floor(0.5+angle_error/360.0);
printf("%12.3f angle_error\n\n",angle_error);
}
int main(void){
test(2,359);
test(354,4);
return 0;
}
Here's the output: Code:
2.000 target
359.000 measured
3.000 angle_error
354.000 target
4.000 measured
-10.000 angle_error
Last edited by Ether : 26-05-2011 at 16:35. |
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#13
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Re: PID crossing 0
I found another way to make it work.
I added a bit of code that subtracts current from target, and then adds or subtracts 2pi. it then comapres the absolute values of the initial subtraction and the adjusted and selects the lesser of the two a way of psudo-wrapping i guess. i will attach a .zip of the code for anybody who wants to see what is going on in the next post. |
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#14
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Re: PID crossing 0
Please post a counter-example showing what doesn't work with the code I posted. If there's a problem with it, I want to know.
Last edited by Ether : 26-05-2011 at 16:41. |
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