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Parabolic vs Air Drag Trajectory revC is the same as revB except the graph is not auto-scaling. Some folks may prefer this.
Parabolic vs Air Drag Trajectory revB fixes a small error: the "launch height" user input parameter was not being imported into the parabola equation.
The physics and math for the computer numerical simulation (including topspin/backspin)
is explained in this paper.
Parabolic Equations and constants a, b, c, xp, and yp
y = a*x2 + b*x + c and y = a*(x-xp)2 + yp explained:
http://www.chiefdelphi.com/media/papers/download/3868
How to find constants a and b, given launch speed and angle:
http://www.chiefdelphi.com/media/papers/download/3871
How to find constants a and b, given desired scoring range:
http://www.chiefdelphi.com/media/papers/download/3872
How to find constants a and b, given yp and a point (x1,y1) on the trajectory:
http://www.chiefdelphi.com/media/papers/download/3877
Terminal Velocity calculator spreadsheet:
http://www.chiefdelphi.com/media/papers/download/3900
parabola.pdf
given speed&angle, find a&b.gif
scoring_range.gif
compute a&b from yp,x1,y1 rev02.pdf
parabola vs air drag.zip
parabola vs air drag revB.zip
parabola vs air drag revC.zip
Terminal Velocity.zip
given Vo and (d,h) find theta.pdf
27-02-2014 18:23
Ether
For those of you who downloaded the Parabolic vs Air Drag Trajectory spreadsheet, please note that I just uploaded revB to correct a small error. The user input "launch height" was not being imported into the parabola equation.
28-02-2014 12:07
Ether|
For those of you who downloaded the Parabolic vs Air Drag Trajectory spreadsheet, please note that I just uploaded revB to correct a small error. The user input "launch height" was not being imported into the parabola equation.
|
The parabola plot with the original version was correct as long as you didn't change the launch height.
And even if you did change the launch height, the error affected only the parabola, not the air-drag trajectory.
04-03-2014 09:55
Hugh Meyer
Ether,
Would you more clearly define the launch angle? A drawing would be nice. Is that from the horizon, or a plumb line? Thanks.
-Hugh
04-03-2014 10:19
Ether|
Would you more clearly define the launch angle? Is that from the horizon, or a plumb line?
|
04-03-2014 10:36
Hugh Meyer
Thank you.
We do not have any data, but we have been talking about it. How would we measure the terminal velocity?
-Hugh
04-03-2014 12:23
marccenterEther,
The assumption appears reasonable with the shooting range we are seeing on our robot.
I just found the thread today. When we unbag the robot on Saturday, I will be attempting to increase our shooting percentage via angle and may be able to provide some data after that point.
We did overshoot the target a bit last weekend at Southfield, MI a few more times than I would have liked.
04-03-2014 12:28
Ether|
The assumption appears reasonable with the shooting range we are seeing on our robot.
|
04-03-2014 14:00
Ether
17-02-2016 19:15
Ether
Given launch speed and a desired point (d,h) on the trajectory, show the derivation of and formulas for the launch angles and the equations of the two parabolic (no air drag) solutions.
http://www.chiefdelphi.com/media/papers/download/4614
17-02-2016 23:44
GeeTwo