So looking at the notes and doing some math, one of my teammates came up with this question:
The low bar’s hole is 16 inches, however there is a foot ramp 3 inches tall, and using basic trig, the angled height of entry comes out to be somewhere around 14 inches or so.
And give a 2-5 inches for ground clearance, and some wheel diameters, and you’re left with basically only an inch or two to work with.
Thoughts?
You’ve been sniped.
But yes, your math is sound.
You are correct about the 14" “true” opening, but ground clearance is not added to the wheel diameter. Unless you’re using some truly crazy wheels, any FRC drivetrain by itself should fit under just fine. It’s the non drivetrain bits which make it tricky.
Thank you both for your responses. My teammate talked with our mentor, and we agreed that we would be able, due to Center of Gravity and only having 4 wheels, to fit under the bar; i.e. flop back down instead of sticking out straight.
What about coming back through the low bar from the other side? What kind of apparatuses would you have. It looks even shorter.
The short side of the low bar is facing the neutral zone. Always harder to get in the castle then it is to get out 
You may want to have a look at the thread linked below. The low bar is not centered on the platform. Your wheels are not located such that their contact point with the floor is directly under the outer edge of your frame. This means that by doing some extra work, you can ensure that your robot to be as tall as possible to make it easier for you to package all your components and mechanism yet still pass under the low bar. If you get this wrong, you could be stuck on the competition field or you will have a hard time building and maintaining your robot.