Does not compute.
For the FP @ 10.5 volts and 35 amps it says
0.222 Nm, 623.7 rad/sec… = 138 watts, not 180 watts.
The spreadsheet is pretty busy. Am I reading it wrong?
**
cim w/ 1:12 gearbox, fp w/ 1:6
How did you come up with these numbers?
my head, since the RPm of an Fp motor is roughly double that of a cim, the cim will have to travel twice as fast
CIM max power is 337 watts @ 2655 RPM
FP max power is 184 watts @ 7500 RPM
Total max power is 521 watts
sqrt(521*81500) = 6516.25
6516.25/2655 = 2.45
6516.25/7500 = 0.869 = 1/1.15
But why increase either motor’s speed by a factor of 6? What led to that decision?
(though it’s worth noting that it’s closer to 3.5 times…
15600/5310 = 2.94
**
Looks good.
The data I have here shows the FP max power 184W at 7800 rpm. The FP would draw slightly less current and run cooler if geared for 7800 instead of 7500.
**
I just noticed: how did you add 337+184 and get 674 ?
**
… Ill advisedly.
Wow. Not sure what happened there. I’ll have to check the excel sheet I made, tomorrow.
Edit to add:
Apparently I mis-clicked in excel, and selected the CIM motor’s output power twice. Oops!